Georgians and Ohioans pay less for dental care than the national average
Research Activities, December 2009, No. 352
The annual amount spent by Georgians and Ohioans or their insurers for dental care in 2006 averaged about $150 less than the national average of $607, according to the latest data from the Agency for Healthcare Research and Quality (AHRQ). The average annual dental expenditure for each Georgian who had dental care was $466, while for Ohioans, it was $474.
AHRQ's analysis of average annual dental expenditures in the 10 States with the highest populations in 2006 also found that:
- Michigan had the highest proportion of residents with dental expenses (52.5 percent) and Texas had the least (30 percent).
- Compared to the national average of 49 percent for out-of-pocket payment for dental care, Floridians paid more (62.5 percent) and Pennsylvanians paid less (42 percent).
- Nationally, private insurers paid 43 percent of all dental expenditures.
These findings are taken from the Medical Expenditure Panel Survey (MEPS), a detailed source of information on the health services used by Americans, the frequency with which they are used, the cost of those services, and how they are paid. For more information, go to Dental Expenditures in the 10 Largest States, 2006 at http://meps.ahrq.gov/mepsweb/data_files/publications/st263/stat263.shtml.
Return to Contents
Proceed to Next Article
Page last reviewed December 2009
Internet Citation: Georgians and Ohioans pay less for dental care than the national average: Research Activities, December 2009, No. 352.
December 2009. Agency for Healthcare Research and Quality, Rockville, MD. https://archive.ahrq.gov/news/newsletters/research-activities/dec09/1209RA32.html